NAG Library Manual, Mark 30
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NAG CL Interface Introduction
Example description

nag_ode_bvp_coll_nlin_contin (d02txc) Example Program Results


 Tolerance =  1.0e-05  l =   60.000  s = 0.2400
(User-supplied callback guess, first invocation.)
(User-supplied callback gafun, first invocation.)
(User-supplied callback gajac, first invocation.)
(User-supplied callback gbfun, first invocation.)
(User-supplied callback gbjac, first invocation.)
(User-supplied callback ffun, first invocation.)
(User-supplied callback fjac, first invocation.)

 Used a mesh of   21  points
 Maximum error =   2.66e-08  in interval    7  for component    1 


 Solution on original interval:
     x        f          g
    0.00     0.0000     0.0000 
    2.00    -0.9769     0.8011 
    4.00    -2.0900     1.1459 
    6.00    -2.6093     1.2389 
    8.00    -2.5498     1.1794 
   10.00    -2.1397     1.0478 
   12.00    -1.7176     0.9395 
   14.00    -1.5465     0.9206 
   16.00    -1.6127     0.9630 
   18.00    -1.7466     1.0068 
   20.00    -1.8286     1.0244 
   22.00    -1.8338     1.0185 
   24.00    -1.7956     1.0041 
   26.00    -1.7582     0.9940 
   28.00    -1.7445     0.9926 
   30.00    -1.7515     0.9965 
   33.00    -1.7695     1.0019 
   36.00    -1.7730     1.0018 
   39.00    -1.7673     0.9998 
   42.00    -1.7645     0.9993 
   45.00    -1.7659     0.9999 
   48.00    -1.7672     1.0002 
   51.00    -1.7671     1.0001 
   54.00    -1.7666     0.9999 
   57.00    -1.7665     0.9999 
   60.00    -1.7666     1.0000 

 Tolerance =  1.0e-05  l =  120.000  s = 0.1440

 Used a mesh of   21  points
 Maximum error =   6.88e-06  in interval    7  for component    2 


 Solution on original interval:
     x        f          g
    0.00     0.0000     0.0000 
    2.00    -1.1406     0.7317 
    4.00    -2.6531     1.1315 
    6.00    -3.6721     1.3250 
    8.00    -4.0539     1.3707 
   10.00    -3.8285     1.3003 
   12.00    -3.1339     1.1407 
   14.00    -2.2469     0.9424 
   16.00    -1.6146     0.8201 
   18.00    -1.5472     0.8549 
   20.00    -1.8483     0.9623 
   22.00    -2.1761     1.0471 
   24.00    -2.3451     1.0778 
   26.00    -2.3236     1.0600 
   28.00    -2.1784     1.0165 
   30.00    -2.0214     0.9775 
   39.00    -2.1109     1.0155 
   48.00    -2.0362     0.9931 
   57.00    -2.0709     1.0023 
   66.00    -2.0588     0.9995 
   75.00    -2.0616     1.0000 
   84.00    -2.0615     1.0001 
   93.00    -2.0611     0.9999 
  102.00    -2.0614     1.0000 
  111.00    -2.0613     1.0000 
  120.00    -2.0613     1.0000 

 Tolerance =  1.0e-05  l =  240.000  s = 0.0864

 Used a mesh of   81  points
 Maximum error =   3.30e-07  in interval   19  for component    2 


 Solution on original interval:
     x        f          g
    0.00     0.0000     0.0000 
    2.00    -1.2756     0.6404 
    4.00    -3.1604     1.0463 
    6.00    -4.7459     1.3011 
    8.00    -5.8265     1.4467 
   10.00    -6.3412     1.5036 
   12.00    -6.2862     1.4824 
   14.00    -5.6976     1.3886 
   16.00    -4.6568     1.2263 
   18.00    -3.3226     1.0042 
   20.00    -2.0328     0.7718 
   22.00    -1.4035     0.6943 
   24.00    -1.6603     0.8218 
   26.00    -2.2975     0.9928 
   28.00    -2.8661     1.1139 
   30.00    -3.1641     1.1641 
   51.00    -2.5307     1.0279 
   72.00    -2.3520     0.9919 
   93.00    -2.3674     0.9975 
  114.00    -2.3799     1.0003 
  135.00    -2.3800     1.0002 
  156.00    -2.3792     1.0000 
  177.00    -2.3791     1.0000 
  198.00    -2.3792     1.0000 
  219.00    -2.3792     1.0000 
  240.00    -2.3792     1.0000