NAG Library Manual, Mark 29.3
Interfaces:  FL   CL   CPP   AD 

NAG FL Interface Introduction
Example description

 D02QFF Example Program Results

 Root at   0.00000E+00
 for event equation  2 with type  1 and residual   0.00000E+00
  Y(1) =   0.00000E+00   Y'(1) =   1.00000E+00

 Root at   1.57076E+00
 for event equation  1 with type  1 and residual  -5.20417E-17
  Y(1) =   1.00003E+00   Y'(1) =  -5.20417E-17

 Root at   3.14151E+00
 for event equation  2 with type  1 and residual  -1.27676E-15
  Y(1) =  -1.27676E-15   Y'(1) =  -1.00012E+00

 Root at   4.71228E+00
 for event equation  1 with type  1 and residual   1.67921E-15
  Y(1) =  -1.00010E+00   Y'(1) =   1.67921E-15

 Root at   6.28306E+00
 for event equation  2 with type  1 and residual   2.65066E-15
  Y(1) =   2.65066E-15   Y'(1) =   9.99979E-01

 Root at   7.85379E+00
 for event equation  1 with type  4 and residual  -7.63278E-17
  Y(1) =   9.99970E-01   Y'(1) =  -7.63278E-17

 Root at   9.42469E+00
 for event equation  2 with type  4 and residual  -6.86950E-16
  Y(1) =  -6.86950E-16   Y'(1) =  -9.99854E-01