Example description

 D02TYF Example Program Results



 Tolerance =  0.1E-04 A =     1.00

 Used a mesh of   11 points
 Maximum error =   0.31E-05  in interval    1 for component    1


 Mesh points:
   1(1) 0.0000E+00   2(3) 0.1000E+00   3(2) 0.2000E+00   4(3) 0.3000E+00
   5(2) 0.4000E+00   6(3) 0.5000E+00   7(2) 0.6000E+00   8(3) 0.7000E+00
   9(2) 0.8000E+00  10(3) 0.9000E+00  11(1) 0.1000E+01

 Computed solution
       x     solution   derivative
     0.00    1.00000   -1.84496
     0.10    0.84944   -1.32330
     0.20    0.72721   -1.13911
     0.30    0.61927   -1.02776
     0.40    0.52040   -0.95468
     0.50    0.42754   -0.90583
     0.60    0.33867   -0.87372
     0.70    0.25239   -0.85369
     0.80    0.16764   -0.84248
     0.90    0.08368   -0.83756
     1.00    0.00000   -0.83655