NAG Library Manual, Mark 27.2
Interfaces:  FL   CL   CPP   AD 

NAG FL Interface Introduction
Example description

 E04YAF Example Program Results

 The test point is
    0.19000  -1.34000   0.88000

 1st derivatives are consistent with residual values

 At the test point, LSQFUN gives

       Residuals                   1st derivatives
      -2.029E-03      1.000E+00     -4.061E-02     -2.707E-03
      -1.076E-01      1.000E+00     -9.689E-02     -1.384E-02
      -2.330E-01      1.000E+00     -1.785E-01     -4.120E-02
      -3.785E-01      1.000E+00     -3.043E-01     -1.014E-01
      -5.836E-01      1.000E+00     -5.144E-01     -2.338E-01
      -8.689E-01      1.000E+00     -9.100E-01     -5.460E-01
      -1.346E+00      1.000E+00     -1.810E+00     -1.408E+00
      -2.374E+00      1.000E+00     -4.726E+00     -4.726E+00
      -2.975E+00      1.000E+00     -6.076E+00     -6.076E+00
      -4.013E+00      1.000E+00     -7.876E+00     -7.876E+00
      -5.323E+00      1.000E+00     -1.040E+01     -1.040E+01
      -7.292E+00      1.000E+00     -1.418E+01     -1.418E+01
      -1.057E+01      1.000E+00     -2.048E+01     -2.048E+01
      -1.713E+01      1.000E+00     -3.308E+01     -3.308E+01
      -3.681E+01      1.000E+00     -7.089E+01     -7.089E+01