Example description

 C02ABF Example Program Results

 Basic Problem

  i    z                      conv  berr      cond
 -----------------------------------------------------
  1  (  1.15E+00,  7.36E-01)    3   5.37E-18  1.34E+01
  2  ( -1.67E+00,  3.25E-01)    3   6.25E-18  2.20E+01
  3  (  3.79E-01, -1.25E+00)    3   1.66E-18  1.02E+01
  4  ( -1.67E+00, -3.25E-01)    3   6.25E-18  2.20E+01
  5  (  1.15E+00, -7.36E-01)    3   6.45E-18  1.34E+01
  6  (  3.79E-01,  1.25E+00)    2   1.66E-18  1.02E+01